x^2+15x+44=(x+2)(x+4)

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Solution for x^2+15x+44=(x+2)(x+4) equation: 



x^2+15x+44=(x+2)(x+4)

We move all terms to the left:

x^2+15x+44-((x+2)(x+4))=0

We multiply parentheses ..

x^2-((+x^2+4x+2x+8))+15x+44=0



We calculate terms in parentheses: -((+x^2+4x+2x+8)), so:

(+x^2+4x+2x+8)

We get rid of parentheses

x^2+4x+2x+8

We add all the numbers together, and all the variables

x^2+6x+8

Back to the equation:

-(x^2+6x+8)



We add all the numbers together, and all the variables

x^2+15x-(x^2+6x+8)+44=0

We get rid of parentheses

x^2-x^2+15x-6x-8+44=0

We add all the numbers together, and all the variables

9x+36=0

We move all terms containing x to the left, all other terms to the right

9x=-36

x=-36/9

x=-4

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